Everybody loves a good puzzle. There’s a certain satisfaction in figuring out the answer to a difficult riddle. Plus, research shows riddles and puzzles keep your brain sharp in old age.

The internet is a repository of mind-bending puzzles 7 Online Riddle Games to Keep You Glued to Your Computer 7 Online Riddle Games to Keep You Glued to Your Computer Looking for some tough puzzles to crack? These free online riddle games will give you plenty of challenges to solve. Read More . But many of these require you to have technical skills, like looking up the source code of a page for clues or altering image files. Logic should test your brain, not your computer skills.

We can’t say if these are the “hardest” puzzles online. What we can say for sure is that these five brain-teasing sites are loved by anyone who likes solving stuff.

## NSA’s Puzzle Periodical (Web): One Difficult New Puzzle, Every Month

The National Security Agency has a bad rep among internet users because of its spying and infringements of privacy Who Is Fighting On Your Behalf Against The NSA And For Privacy? Who Is Fighting On Your Behalf Against The NSA And For Privacy? There are several Internet activism groups who are fighting on your behalf for privacy. They are doing their best to educate netizens as well. Here are just a few of them that are incredibly active. Read More . Set that aside for a minute and you’ll know that some of the brightest minds work there. And every month, one of these bright minds submits a puzzle for the world to figure out.

The NSA Puzzle Periodical was started only last year, so there isn’t a large collection waiting for you. But you can still browse through logic puzzles, written precisely and exquisitely. Most importantly, it’s a new puzzle every month!

The answer is posted a few days after the question, so feel free to discuss it with others till then. There are no trick questions or cheap answers, as far as I can make out.

## Sudoku Escargot (Web): The Hardest Sudoku Ever

You’re probably familiar with the numbers-oriented game of Sudoku. It’s a stress-free way to give your brain a 5-minute workout 5 Things You Can Do in 5 Minutes to Exercise Your Brain 5 Things You Can Do in 5 Minutes to Exercise Your Brain Keeping your brain in top shape requires that you challenge it on a regular basis. Surprisingly, you can do a lot in five minutes. Here are five things you can do for your mental fitness. Read More . You might already be pretty good at it. But do you think you can solve the hardest Sudoku puzzle ever made?

Mathematician Arto Inkala built an algorithm to generate challenging Sudokus, called AI Sudoku. And this is the most difficult one the bot ever created. It’s called the Escargot, and on his blog, Inkala explains why it’s the most difficult Sudoku.

Try solving it on Sudoku Wiki or print it out and take it with you. No matter how you choose to tackle this, make sure you have plenty of time. And Inkala’s blog post linked above also has 19 other super-difficult Sudokus for you to solve.

## Blue Eyes (Web): XKCD’s “Hardest Logic Puzzle”

I love getting a difficult puzzle that I can slowly work on, over several days or weeks. The joy of a good riddle lies as much in the journey. If you’re patient with puzzles, then read “the hardest logic puzzle in the world,” according to XKCD.

For the uninitiated, XKCD is one of the best webcomics for geeks 10 Awesome Webcomics Drawn Just for Geeks 10 Awesome Webcomics Drawn Just for Geeks Webcomics are arguably more popular now than they ever have been before. This is mainly due to a marked increase in the quality of content, with some webcomics being both magnificently written and magnificently drawn.... Read More , often talking about logic, math, and lateral thinking. Its creator shared this puzzle (which he heard from someone else) in the simplest language possible. No word play, no double meanings, or anything else.

Read the riddle, digest every information from it, and set about working it out in your head. You’ll find yourself thinking about it whenever you have some time.

## 101 Friday Puzzles (Web): Richard Wiseman’s 101 Brainteasers

Noted psychologist Richard Wiseman is a bit of an internet celebrity. He is known for amazing illusions that blow your mind 5 Mind-Blowing Web Sites That Will Make You Go Wow 5 Mind-Blowing Web Sites That Will Make You Go Wow The internet is full of magic. Amazing music videos, magic tricks, and optical illusions done with the help of cutting edge technology will make you go "wow". Read More on his YouTube channel, he is a noted expert on magic and psychology, and he is a famed logician.

Every Friday, Wiseman shares a puzzle or riddle on his blog, challenging readers to solve it. The puzzles use a combination of linear and lateral thinking, so some answers will require creative thinking.

You’ll find matchstick problems, logical riddles, and some picture-based puzzles too. There are 101 to get through, so save this page for offline reading wherever.

## Logic Mazes (Web): Robert Abbott’s Famous Puzzles

Logician, programmer, and game inventor Robert Abbott has been designing games since the 1950s. Abbott pioneered the concept of “logic mazes”, and some of his best ones are available online for free.

A logic maze is a maze or a grid with some set rules. For example, the Easy Maze 1 dictates you can never turn left. So without turning left, how do you travel from the start to the finish line?

Abbott also makes interactive puzzles that are hosted on the site, so you can “play” instead them to solve. Trust me, you’re going to need that little interactivity if you want any hope of getting through these.

## Can You Solve This?

You can solve any of the logic questions above, or you can try your hand at figuring out this fun puzzle.

You have 16 marbles and a balancing scale. One of the marbles is heavier or lighter than the others, while 15 are the same weight. Using the scales three times or less, identify the odd marble and whether it’s heavier or lighter.

**Tell us your answer in the comments below!**

Explore more about: Cool Web Apps, Puzzle Games.

WHAT IS THE SOLUTION TO THE EYE ONE SOMEONE PLEASE!!!!

All 100 blue eyed people leave on the 100th night

I can do the marbles riddle in exactly one weigh. But I have to be allowed to move the pieces on the scale plates.

Whats the solution to the eye one???

It's very simple but, in my opinion the logic question it's stupid. Why someone wants to identify a different marble from a pile of marbles and to use a balancing scale when we have electronic scales ? This is really stupid ! If you put the logic question in a different situation and in the right period of time when the balanced scale was used, then we can talk about it. "You have a big pile of gold coins and you must use the balancing scale as fewer times as you can to identify the coins that are unbalanced or the ones that are fake in order to punish the counterfeiters. So here is a problem : we have 16 coins and one of those is unbalanced, while 15 are the same weight. Using the scales three times or less, identify the odd coin and whether it’s heavier or lighter. If it's much lighter or if it's heavier and made from other metals then the owner goes to jail ".

The solution depends on luck :

1). We take 8 coins and balance 4 with 4. If those are balanced then in the other 8 we find the odd one, if not then we find it in this 8 that we just measured.

2). We take 4 of the 8 unbalanced coins and balance 2 with 2. If we are lucky and this 4 coins are unbalanced then we can end the measurement here because we know where the odd one is so now we can take only one coin from the balanced scale and continue with the moves from the third measurement, otherwise the unbalanced coin is with the other 4.

3). We balance 1 with 2 coins from the unbalanced 4, and if the ratio is 1 to 2 then we know that the fourth coin is the odd one and we add to the measurement the odd coin so we balance 2 with 2 coins again, and that's how we will find out the weight. If the ratio is not 1 to 2 then we know that the fourth one it's ordinary coin and now at the third measurement we have to make some coin moves to find out which is the odd coin and how much does it weight. So in order to do that we must take one coin from the pile of 2 and find out if the remaining coins are balanced or not (if the coins are balanced then we took the odd one if not then we know that the two coins that we have are ordinary so we pay attention at the weight ratio of the two balanced coins in order to determine the odd coin at last movement), and then we move together the coins that are on scale and balance those with the tow coins that we have left and then we will find out the weight and the odd coin. Technically this moves means that there are more than 3 measurements but practically, because one of the coins is not moved at all it means that the moves are made the same measurement. And that's how I can explain using the scales three times or two times depending on luck.

Only looked at the dog and maze puzzles tbh. Cracked both in a few seconds lol dog one - move the upper part of the head matchstick to the other end of the body so when the tail matchstick is moved down it makes a head with it. The remaining matchstick that was part of the original head is now the tail pointing up. Obviously the paper ball is moved too. The maze one - you would have to go through the maze backwards then it would be 2 right turns to get to the ‘goal’ well this is imo lol :)

You have to follow the arrows as it is shown on the maze.

U have to follow the arrows u cant go backwards.

If we focus on grammar then it says "using the SCALES " it is not one scale we can use we can use many scales but less than 3 or 3 times , otherwise....

For the maze, you could go up and then down which would make the left a right coming from the opposite direction. So if you would need to make a left just go up and come back down the same path and it'll be a right. Right??

Why thought moving back word is the solution.

For the maze, you could go up but then go down the same way making left a right. So that every time you have to make a left you just come the opposite way making it a right. Ya know?

Well actually I did solve it. I'm 15. You can solve it. The way you make it sound is confusing to others but not me.

(1)2*8 =>(2)2*3=>(3)1~1,1

Well, take out one of the marbles at random.Now we have 15 marbles and one which is different or not.Divide the 15 marbles into 3 equal piles.

Case 1: If the one we took out was the different one,then by 2 comparisons of the 3 equal piles we can say that the one we took is the different one and comparing it with any other marble we can say how it differs (heavy or light).Thus by weighing 3 times we could solve it.

Case 2: If the different marble is in one of the piles, we can easily compare the 3 piles to find

how the whole pile containing the different marble weights lighter or heavier.Thus by weighing 2 times we could solve it:)

Can not be done with 16 Marbles in 3 weighings !

Only 12 Marbles can be handled in 3 weighings !

You are right it cannot be done but the maximum number of marbles in 3 weighings is in fact 13.

Sorry that should read 12

Sorry, that should read 12.

If only a simple balance is used weighing the given balls against each other then only 12 balls can be handled in 3 weighings.

If extra standard balls are available say 9 more then 13 balls can be solved in 3 weighings.

This puzzle is impossible.

I can only imagine there is a typo which should have read 12 marbles. Only a maximum of 12 marbles can be solved in 3 weighings to find the odd marble and tell whether it is lighter or heavier. You have to go to four weighings to solve 13 to 39 marbles.

1: 6 + 6 marbles. If the same weight, the heavy marble is one of the 4 at the table

2: 2 + 2 marbles.

3: 1 + 1 from the heaviest side, and there it is

Or

If one of the 6 are heavier:

2: 3 + 3 marbles on the scale.

3: 1 + 1 marble on the scale from the heaviest side, and one at the table. If scale is levelled; the heavy marble is at the table, if not; the scale will tell

:-)

That only finds the heavier one, but doesn't solve the problem for a lighter one.

7 7 at both sides

So here r 3 equation

1,. 7 = 7 then rest 2 weight 1 1 we will get the and in weights

2,. 7 >7

3 3. 1

If sq then 1

3 , 7 left is lighter than 7 wirigjt

Let's say left scale is heavier. Which party are you going to choose to scale further ? The heavy group or the light group ? It can be either one.

It's always easier, at least emotionally, to solve/(re)solve logical puzzles than logical problems.

Puzzles come with an assumed advantage of knowing there is a solution with very little life consequences/conclusions involved in the solving.

Very interesting puzzles. I could play them to train my brain.

I will have 6 marbles on both side of scales

If they are equal

I will have rest 4 with 2 in each side

whichever side is heavier

i will have one in each side from heavier lot

If any of the side having 6 marble is heavier

I will pick those 6

Will have 3 each in both the sides

From whichever is heavier i will pick two and have them 1 each in both sides.

If they are equal third one is heavier

This doesn't work if one is lighter.

Yes i should have replaced heavier with heavier or lighter